Why does $t^{\frac{3}{2}} \cdot t^{\frac{1}{2}} = t^2$?
What I tried to do was multiply the exponents together $\frac{3}{2} \cdot \frac{1}{2} = \frac{3}{4}$ so my final answer was $t^{\frac{3}{4}}$ but according to my Wileyplus homework it is $t^2$.
Can someone please explain?
When multiplying two of the same number raised to exponents (such as ${x^\frac{3}{2}}$ times $x^{\frac{1}{2}}$) you add the exponents.
$$x^a \cdot x^b = x^{a+b}$$
Only when raising a number to an exponent, and raising the result to an exponent do you multiply exponents together.
$$(x^a)^b = x^{a\cdot b}$$
Note: $(x^{a})^{b} \neq x^{(a^b)}$