Probability Poisson distribution customer service

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So my question is: Assume the number of customers calling customer service is Poisson distributed, with an average rate of $10$ customers per minute. What is the probability that no one calls in a one-minute period?

So I've defined my random variable as $X$ representing the number of customers that call in the next minute. $X \sim Poisson(\lambda=10)$. When I plug all these into my poisson distribution formula I get indefinite because zero ends up being the denominator. I'm a little confused so I would love some help! Thanks

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Poisson pmf is of the form of $$\exp(-\lambda) \frac{\lambda^x}{x!}$$

Notice that $0!=1$.