As in the title. Here are my attempts and the given function:
Given function: $y=\frac {\log_2{x}-3}{2x} $
Inverse function: $$ x= \frac {\log_2{y}-3}{2y} $$ $$2xy=\log_2{y}-3 $$ $$ 2^{2xy}=\frac y8 $$
At this step i'm stuck, and dont know what to do next