Using the rules below prove that the following assumeptions leads to the following conclusion by tautology.
$A\vee B \vee C, A\to C, B\to C \Rightarrow C$
What I did:
- $A\vee B \vee C$ Assumption
- $A\to C$ Assumption
- $B\to C$ Assumption
- $A\vee B\to C$ rule 11 on lines 2,3
- $\neg\neg(A\lor B \lor C)$ rule 7 on line 1
- $\neg (\neg A\land \neg B \land \neg C)$ rule 14 on line 5
- $\neg\neg A$ rule 3 on line 6
- $A$ rule 7 on line 7
- $A\vee B$ rule 5 on line 8
- $C$ rule 1 on line 4, 9 $\square$
But there seems to be a problem since I get that $(A\vee B \vee C)\to A$ which can't be right... So what am I doing wrong here?

I use Polish/Lukasiewicz notation.
Rule 1 says
Rule 11 (R11) says
Thus, we'll derive a rule first, which I'll denote R16. The rule is Cac, Cbc, Aab -> c.
Now we'll solve the problem:
where T13 is Caa or any substitution instance of it such as Ccc.