I wonder how to solve this system of equations: $\begin{cases} 2x^2+y^2=43\\2x^2+4xy=78\end{cases}$
when I subtract I have $y(4x-y)=35$ but I don't if it is good way to look for the solutions.
2026-04-22 16:41:14.1776876074
Problem with system of equations
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Adding both the equations gives you : $$4x^2 + 4xy + y^2 = 121$$ $$(2x+y)^2 = 121$$ You will get $y$ in terms of $x$ from this equation which you can substitute in the given equation, solve the quadratic equation, find $x$ and eventually $y$.