Procedure about simplifying radicals

Question

I have this:

$$\frac {(2n+1)^3-8n(n^2-1)}{\sqrt{n(n+1)(n+2)(n+3)}}=\sqrt{\frac{144n^4+336n^3+220n^2+28n+1}{n(n+1)(n+2)(n+3)}}$$

What does this mean? What's the step by step procedure to do this?

Thanks :)

Answer 1

$n=\sqrt{n^2}$ for any nonnegative real $n$, so $$\frac{n}{\sqrt{m}}=\frac{\sqrt{n^2}}{\sqrt{m}}=\sqrt{\frac{n^2}{m}}.$$ Does this help?