Product metric, continuity of functions and minimum

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Suppose there are $n$ metric spaces $(X_i,d_i)$, and $X$ being the product space with the product metric $\rho$.

In proving that the projection function $\pi_i(x_1,...,x_n) = x_i$ is continuous, the proof follows something like this (not rigorous since it's only serving to motivate the question):


Fix $\varepsilon > 0$. Then we get the existence of $\delta := \varepsilon *2^{-i}$ such that

$\rho(x,y)$ = $\sum_{j=1}^{n} 2^{-j} min(1, d_j(x_j,y_j))$ < $\delta$

Implies that, for a specific $i$,

$2^{-i}d_i(x_i,y_i) \leq \sum_{j=1}^{n} 2^{-j} min\{1, d_j(x_j,y_j)\} < \delta$ (1)

So $d_i(x_i,y_i) < \varepsilon$ and the function is continuous.


In this proof, it actually follows that we can, without lose of generality, consider $min\{1,d_i(x_i,y_i)\}$ as $d_i(x_i,y_i)$, in (1). I would like to know why that is the case.

Thanks

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Let p = $\pi_i:X_1×..×X_n$ -> $X_i, (x_1,.. x_n)$ -> $x_i.$
To show p is continuous, let U be any open subset of $X_i$
and show $p^{-1}(U) is open. This will also show
projections of infinite products are continuous.

In fact without much ado the projections can be shown to be open.