Alright so I am having the following issue: I want to figure out how to find the fourier coefficients of the following function: $$D(X)=\frac {a'(x)} {1+a'(x)^2}$$
Where $a(x)$ is an arbitrary function. I already have a model for finding the fourier coefficients for $a(x)$ and $a'(x)$:
fc = fft(a) / Nfft;
fc = fftshift(fc); % fft of a(x)
fc = conj(fc); % sign correction
aprimec = -i * [0:Dim2-1] .* fc; % fc of derivative (definition)
The equation I am given to use is: $$f_m=\frac 1 N \sum^Nf_ie^{+im2\pi x}$$
Which confuses me because of the $f_i$. So does any one have any suggestions?
Additionally, I do not know how to define d
d = diff(a)/(1+diff(a)^2);
I do not think that this would work because doesn't diff(x) just take the difference between two consecutive components in the vector?
I would greatly appreciate any help. Thanks!
You can try to approximate $D$ using the
ifftof $a'$, additionally your formula seems to be $$ \hat{f}_m = \frac{1}{N} \sum_{j=0}^{N-1} f_j \omega_N^{mj} $$ where $\omega_N = \exp(\frac{2\pi i}{N})$.