Given $\mathbf{x}$^$\mathbf{a}$=$\mathbf{b-x}$
Prove
$(a^2+1)\mathbf{x}=\mathbf{a}$^$\mathbf{b+b(a.b)a}$
I have been using this same dot product and crossproduct method, but don't get it.
The method I used is similar to a question that I recently posted here.