The book Algebraic number fields, Janusz 
Please, Could you explain the proof of the part b) a little more?
Thank you all.
The book Algebraic number fields, Janusz 
Please, Could you explain the proof of the part b) a little more?
Thank you all.
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Note that
$$\text{Re}\,s:=\sigma>b\implies \left|\sum_{n=1}^\infty\frac{a(n)}{n^s}\right|\le\sum_{n=1}^\infty\frac{|a(n)|}{n^{\sigma}}\le\sum_{n=1}^\infty\frac{|a(n)|}{n^b}$$
and now use (a) and the fact the last series is uniformly convergent and etc.
I suppose Janusz is assuming Weierstrass M-test or something like that to deduce that a uniformly convergent series of analytic functions is analytic, or may you can prove it directly as it is not, if I recall correctly, that hard.