Here is a translation i am using for my studies :
http://www.research.ibm.com/people/h/hirzel/papers/canon00-goedel.pdf
it seems like a silly question, but i can't find a way, how do i prove (0=0) inside gödel's system ?
I feel like i have a solid intuition of the construction of the undecidable statement. Yet there are some parts i can't prove by myself, especially the theorem V.
I am trying to adapt the proof from Peter Smith's book, showing that "his" system P is "primitive-recursive adequate", but i don't know how to adapt it in godel's context and being unable to prove that (0=0) prevents me from carrying on my adaptation :
(p.125) "The successor function $\ Sx = y$ (outside of the theory) us captured by the open well formed formula Sx = y (inside the theory)
Gödel's system seems to lack an axiom :
http://web.mit.edu/24.242/www/PeanoArithmetic.pdf
(page2) "Proposition 1. $\ PA |- (\forall x) ((x=0) \lor ((\exists y)x=Sy)) $ with $\ S $ being the successor function
that axiom would solve everything but it's not in Gödel's system. I guess Gödel didn't make a mistake so what am i missing ?
Thank you
See your previous post regarding elementary formulae.
Equality is defined in Gödel's system; we have that $x_1=y_1$ is :
that reads : $\forall P [P(x_1) \to P(y_1)]$.
Form the logical law : $P(x_1) \to P(x_1)$ [*], we can derive the immediate consequence [**] : $\forall x_1 \forall P [P(x_1) \to P(x_1)]$, that reads :
Using logical axiom-schema III.1 :
that reads : $\forall v \varphi \to \varphi [v/c]$, with $0$ as $c$ we get, by modus ponens :
Regarding Peano axioms, I'm quite sure that there is no mistake in Gödel's system.
The system is an high-order logic system (this is the reason why he can define equality, instead of using the usual fist-order axioms for it).
The arithmetical axioms used by Gödel are the translation in his own system of the last four axioms of original (second-order) Peano's formulation in Arithmetices principia, nova methodo exposita (1889).
The paper you have linked proves : $\mathsf {PA} \vdash (\forall x)(x = 0 \lor (\exists y) (x = sy))$ [it is a theorem, and not an axiom] using the induction axiom as well as some "theorems of pure logic" .
Having proved in Gödel's system $P$ that $0=0$, with 1.3 of Principia : $\vdash q \to (p \lor q)$ (one of the "theorems of pure logic" needed), we have :
Using equality we have : $sx=sx$, and thus $(\exists y) (sx = sy)$.
Thus, with 1.3 again, we conclude with :
Finally, with 2.02 of Principia : $⊢ q → (p→q)$ we derive :
Now the result follows by a suitable instance of the induction axiom schema and modus ponens.
Notes
[*] The logical part of Gödel's system is W&R's Principia Mathematica; see page 101 for the proof of:
called the "principle of identity".
[**] In your translation one of the two rules of inference is omitted (it seems a typo) but it is used in def.43 IMMEDIATE CONSEQUENCE.
The two inference rules in Gödel's system are described as follows :