Proof of $(\forall x. \varepsilon(x)) \Rightarrow \bot $ in $\lambda\pi $ calculus $\equiv$

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What is the right representation of the proof of $(\forall x. \varepsilon(x)) \Rightarrow \bot $ in simple type theory as a term of $\lambda\pi $ calculus $\equiv$?

Note on notation:

The epsilon takes a propositional content and returns a proposition in the simply typed lambda calculus. The lambda pi calculus modulo is just the usual dependently typed lambda calculus that serves as the metalanguage of LF but with a set of reduction rules