Proof of inner product property: $\langle Ax,x \rangle = \langle x,A^Tx \rangle$

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$A$ is a matrix in $\mathbb{R}^{m \times n}$ and $x \in \mathbb{R}^n$.

I want to prove that: $$\langle Ax, x \rangle = \langle x , A^T x \rangle $$

Having $A^T$ as the transpose of the matrix $A$.


Just realized I use this property so much, yet I don't known how to prove it.

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We have that by definition

$$\langle Ax, x \rangle = (x^TA^T)x=x^T(A^Tx)=\langle x , A^T x \rangle$$

with $A\in \mathbb{R}^{n \times n}$, otherwise

$$\langle Ax, y \rangle = (x^TA^T)y=x^T(A^Ty)=\langle x , A^T y \rangle$$

with $y \in \mathbb{R}^m$.