proof of $\sum_{i=k}^n {i \choose k}= {{n+1}\choose {k+1}}$ with another formula

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I'm on an exercise for the university and have no clue what to do. The exercise is the following: You should proof that $\sum_{i=k}^n {i \choose k}= {{n+1}\choose {k+1}}$ . I've done that with an induction over $n$ and this goes very well.

But the other part is that we should use another formula an that is the following to proof it:

$$\sum_{i=k}^n {{i+1}\choose{k+1}} = \sum_{i=k}^n {i \choose{k+1}} + {i \choose{k}}$$

And there i need your help. Does anyone know what to do with this??

Thanks for your help!