Please, I should verify if is truly each supposition, knowing that (a+b)>(d+c), a>b and c>d
- a>c
- a>d
- b>c
- b>d
That's a problem from my calculus question list. I really need help.
I tried thought induction, with no success.
Please, I should verify if is truly each supposition, knowing that (a+b)>(d+c), a>b and c>d
That's a problem from my calculus question list. I really need help.
I tried thought induction, with no success.
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Only Option 2 is true
Option 1 counterexample: $$a=4,b=3,c=5,d=1$$ Option 3 counterexample: $$a=4,b=3,c=5,d=1$$ Option 4 counterexample: $$a=5,b=1,c=3,d=2$$
Option 2 proof: (where n and m are positive) $$(a+b)>(c+d)$$ $$(a+a-n)>(d+m+d)$$ $$2a>2d+m+n$$ $$2a>2d$$ $$a>d$$