I am trying to prove the following:
I know that there is a proper action of $\mathbb{R}^n$ on $\mathbb{R}^n$, but is it possible to construct a proper action of $\mathbb{R}^n$ on $\mathbb{R}^m$, where $n>m$?
2026-04-12 13:30:40.1776000640
Proper action of $\mathbb{R}^n$
75 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in ALGEBRAIC-TOPOLOGY
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