Prove angles of $(\vec r), (\vec v),(\vec a)$ are constant in this trajectory

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Given the trajectory

$$r(t)=[A\cos(\omega t),B\sin(\omega t+\alpha)]$$

Prove that the angles between $\vec{r}, \vec{v}, \vec{a}$ are constant.

So the first idea is looking at the dot product and then (hopefully) $\cos(\theta), \theta$ being the angle of vectors, wouldn't have a time dependence. However doing all the extensive work it doesn't quite work. How could I do this?