Using Peano axioms, prove
$∀x∀y∀z(x+y=x+z→y=z)$.
I have been stuck on it for some time, could someone please give a proof? Thanks!
Using Peano axioms, prove
$∀x∀y∀z(x+y=x+z→y=z)$.
I have been stuck on it for some time, could someone please give a proof? Thanks!
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HINT
Since from previous posts I know you are working with a set of Peano axioms that recursively define addition and multiplication over the right operand, it will be much easier to prove the right-cancellation law:
$\forall x \forall y \forall z (y + x = z + x \rightarrow y = z)$
You prove this fairly easily by induction over $x$
So then to prove your original theorem, you would need commutation:
$\forall x \forall y \: x+y = y+x$
which itself can be proven using induction.