Prove that, for every x , y, z of the natural inequality is true:
$x\ $ $+$ $y\ $ $+$ $z\ $ $\ge$ $3$ $and$ $x$*$y$*$z$ $=$ $1$
I tried to divide by 3, but does not go :(
2025-01-12 23:31:04.1736724664
Prove inequality of natural x, y, z
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HINT: we have $\frac{x+y+z}{3}\geq \sqrt[3]{xyz}=1$ by AM-GM