$$\mathscr L = \{x \in \{0,1\}^* \mid \text{there is a } y \in \{0,1\}^* \text{ such that } x = yy\}$$
How can I prove that this is not a Regular language? I tried using proof by contradiction but cannot manage to find a solution.
2026-03-25 23:08:37.1774480117
Prove L is not a regular language (A Finite State Automaton cannot accept it)
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Hint- is $L^{\prime} = \{ 0^{n}1^{n} : n \in \mathbb{N} \cup \{0\} \}$ regular? What happens when you take $w \in L^{\prime}$? Is $ww \in \mathcal{L}$?