Prove only 1 solution exists for the following equation $x^2 = y^2 + 71$ where $x, y$ and pos integers

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Hi I've been stuck on this equation for a while. Pretty sure it has something to do with Pell's equation $x^2 - D y^2 = a$. Not exactly sure.

The question:

(i)Prove that there is only one solution to $x^2 = y^2 + 71$ for positive integers $x$ and $y$.

Then part (ii) which I'm capable of doing if I get (i):

(ii) Hence (and not otherwise) prove that there do not exist three consecutive integer values of $n$ for which $71n + 60$ is a perfect square.

If any of you could help me get (i) that would be great.

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