I have to show that the parametric equations of a trochoid are:
$x = r\theta - d\sin\theta$ and $y=r-d\cos\theta$
where r is radius and d is the distance between center of the circle and a point P.
Can someone please explain this to me? I'm in my second week of advanced Calculus, thanks
in the diagram i have drawn i labelled it as point D some where on circle also i have taken the angle to be "a"
from the diagram you can see that point D is online CP and P started initially from origin and it has travelled by an angle of "a" so PR=OR= ra ( PCR is a sector with angle a and arc length ra)
our job is to find the x and y co-ordinates of D which is making the curve
from triangle CDQ
CD=d which is given in our question
CQ= d $cosa$ and DQ= d $sina$
now x-coordinate of point D= OR- DQ
SO x= r*a-d $sina$
and y- coordinate of point D = CR- QR
y=r- d $cosa$
hence the parametric representation of the curve is
x= r*a-d $sina$
y=r- d $cosa$