Prove that if $a_n$ is non-increasing, converges to $0$, and radius of convergence of $\sum_{n = 0}^{\infty} a_n X^n$ is equal to $1$ then this series converges at every point in $[-1,1)$
I am trying to work out this proof using abel's theorem, but I missed the classes where its use as a conditional convergence test was demonstrated. Once I have an idea of how this first proof should go, I think I can also prove a similar result if $a_n$ is non-decreasing on $(-1,1]$ If I am mistaken and using Abel's theorem here is not as easy as Dirichlets or Leibniz then guidance for that direction would also be appreciated.
I'm just going to use $x$ instead of $X$. Since the radius of convergence is $1$, we know that the series converges for every $x\in(-1,1)$. So to show that the series also converges for $x=-1$ we can use the alternating series test since the series would look like $\sum_{n=0}^\infty (-1)^na_n$. The alternating series test says that the series $\sum_{n=0}^\infty (-1)^na_n$ will converge if the sequence $a_n$ is not increasing (monotonically decreasing) and $\lim_{n\to\infty} a_n=0$. Since these conditions are met by hypothesis, we see the series will converge for $x=-1$, however we don't know about when $x=1$.
Hopefully this helps.