Prove that $ a, b, c $ are in arithmetic sequence for the given condition.

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A question on my mathematics textbook, Mathematics—Textbook for Class XI, goes thus:

If $a\left(\frac{1}{b} + \frac{1}{c}\right), b \left(\frac{1}{c} + \frac{1}{a}\right)$ and $c \left(\frac{1}{a} + \frac{1}{b}\right)$ are in arithmetic sequence, prove that $a, b, c$ are also in arithmetic sequence.

I've tried solving the question by proceeding with this as the first step:

\begin{equation} b \left(\frac{1}{c} + \frac{1}{a}\right) - a \left(\frac{1}{b} + \frac{1}{c}\right) = c \left(\frac{1}{a} + \frac{1}{b}\right) - b \left(\frac{1}{c} + \frac{1}{a}\right) \end{equation}

However, I've been unable to reach this step:

\begin{equation} b - a = c - b \end{equation}

which, I believe, is required to arrive at to prove that $a, b, c$ are indeed in arithmetic sequence.

A guidance towards the right steps would be helpful.

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Hint: Let $x_1=a\bigg(\frac{1}{b}+\frac{1}{c}\bigg)$, $x_2=b\bigg(\frac{1}{a}+\frac{1}{c}\bigg)$ and $x_3=c\bigg(\frac{1}{a}+\frac{1}{b}\bigg)$.

Then

$$ x_3-2x_2+x_1=\frac{(ab+ac+bc)(a-2b+c)}{abc} $$

Can you finish from here ?