Let $\xi_n = e^\frac{2\pi i}{5} $. Prove that $\xi_5 \notin \Bbb{Q}(\xi_7)$ where $\Bbb{Q}(\xi_7)$ is the 7-th cyclotomic field.
How would I approach this question? I'm having a difficult time coming up with a solution, any tips would be appreciated
Let $\xi_n = e^\frac{2\pi i}{5} $. Prove that $\xi_5 \notin \Bbb{Q}(\xi_7)$ where $\Bbb{Q}(\xi_7)$ is the 7-th cyclotomic field.
How would I approach this question? I'm having a difficult time coming up with a solution, any tips would be appreciated
Suppose $\;\xi_5\in\Bbb Q(\xi_7)\;$, then
$$\;\phi(5)=4=[\Bbb Q(\xi_5):\Bbb Q]\,\mid\,[\Bbb Q(\xi_7):\Bbb Q]=6=\phi(7)\;$$
and this is absurd.