Prove that for nbelongs to natural number
$$(-1)^1{n\choose1}\dfrac{(1+r\ln10)}{(1+\ln(10^n))^r} +(-1)^2{n\choose2}\dfrac{(1+r\ln10)}{(1+\ln(10^n))^r}+....=0 $$
I have proved this by induction which clearly is not the method
Prove that for nbelongs to natural number
$$(-1)^1{n\choose1}\dfrac{(1+r\ln10)}{(1+\ln(10^n))^r} +(-1)^2{n\choose2}\dfrac{(1+r\ln10)}{(1+\ln(10^n))^r}+....=0 $$
I have proved this by induction which clearly is not the method
Consider the binomial theorem $$(1+x)^n = 1 + \binom{n}{1} x + ... \binom{n}{n} x^n$$
But $x = -1$, we obtain:
$$(-1)^0{n\choose0}+(-1)^1{n\choose1} +(-1)^2{n\choose2}+... (-1)^n{n\choose n} =0$$
Therefore your series evaluates to $-\frac{1+r\ln{10}}{(1+\ln{10})^r}$ for all $n$ (Naturals).