So I have the following $f: \mathbb{R} \rightarrow \mathbb{R}$. Prove that $f$ is odd given the following relation:
$$3f(x) + 2f(-x)=\frac{x}{x^2+1}$$
So I have the following $f: \mathbb{R} \rightarrow \mathbb{R}$. Prove that $f$ is odd given the following relation:
$$3f(x) + 2f(-x)=\frac{x}{x^2+1}$$
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Hint: change $x$ to $-x$, and add the two equations.