If for $1\leq i \leq k$: $a_i$ are postive integers and $k$ is a arbitrary integer , then $\Sigma \sqrt[n]{a_i}$ is rational iff $\forall _i \sqrt[n]{a_i} \in \mathbb{Q}$.
I tried a couple of times, but I still cannot solve it. Thanks in advance.
If for $1\leq i \leq k$: $a_i$ are postive integers and $k$ is a arbitrary integer , then $\Sigma \sqrt[n]{a_i}$ is rational iff $\forall _i \sqrt[n]{a_i} \in \mathbb{Q}$.
I tried a couple of times, but I still cannot solve it. Thanks in advance.
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