Prove that if $m^2+n^2=0$ then $m=0$ and $n=0$.
Given $m^2+n^2=0$ then $m^2= -n^2$. Because $m$ and $n$ are real numbers, then $m^2 \geq 0$, $n^2 \geq 0$. Therefore, $m=0$ and $n=0$.
Is that correct?
Prove that if $m^2+n^2=0$ then $m=0$ and $n=0$.
Given $m^2+n^2=0$ then $m^2= -n^2$. Because $m$ and $n$ are real numbers, then $m^2 \geq 0$, $n^2 \geq 0$. Therefore, $m=0$ and $n=0$.
Is that correct?
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Hint: Use that $$m^2+n^2\geq 2|mn|$$ so $$|mn|\le 0$$