Let $K=\{(x,y,z)\in \Bbb{R}^3\ :\ x^2+yz=x+1\}$
Show that $K$ is not compact
$K$ is "clearly" closed, as the solution set of a continuous function. So the only way it can fail to be compact is to be unbounded.
Now check that $(0, n , \frac{1}{n}) \in K$ for all $n$ and its norm is $>n$.
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$K$ is "clearly" closed, as the solution set of a continuous function. So the only way it can fail to be compact is to be unbounded.
Now check that $(0, n , \frac{1}{n}) \in K$ for all $n$ and its norm is $>n$.