Prove that $L(S\cap T) \subseteq L(S)\cap L(T)$

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I am asked to prove

$L(S\cap T) \subseteq L(S)\cap L(T)$

I am at a complete loss as to where to even start. I understand that they are not equal because for example part of the basis for $S$ could be $e_i$ and for $T$ could be $2e_i$, but how do I prove the above statement? I am not looking for a complete proof but merely a hint to get me started.

Should I maybe write the elements of the two sets as linear combinations of their basis components? Where would I go from there though?

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Well, let $V$ be a vector space over $K$ and let $A,B$ be subsets of $V$. If $A\subseteq B$, then $L(A)\subseteq L(B)$.

In your case, $S\cap T\subseteq S$ and so $L(S\cap T)\subseteq L(S)$. Similarly, $L(S\cap T)\subseteq L(T)$. Therefore, $L(S\cap T)\subseteq L(S)\cap L(T)$.