$□p$, $□q$ therefore, $□(p→q)$
according to the K system of modal logic, the argument is invalid. I tried proving it using a truth tree, but all the branches unfortunately close, I don't know how to proceed.
$□p$, $□q$ therefore, $□(p→q)$
according to the K system of modal logic, the argument is invalid. I tried proving it using a truth tree, but all the branches unfortunately close, I don't know how to proceed.
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