Prove that this function is constant: $$f(x)=\arcsin\left(2x\sqrt{1-x^{2}}\right) - 2\arcsin x$$
2026-03-29 11:42:59.1774784579
Prove that the function is constant $f(x)=\arcsin2x\sqrt{1-x^{2}} - 2\arcsin x$
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Hint:
Let $x=\sin y$ then $\sqrt{1-x^2}=\dots?$
And $\sin2y=\dots?$