I was revising for my final and got this question. I don't see there exists such a language. Is it really existing?
2026-03-26 13:44:39.1774532679
Prove that there exists a language L ⊆ {0}^∗ that is not Turing decidable.
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If $N$ is a subset of $\mathbb{N}$ whose membership problem is not Turing decidable, I think that $\{x \in \{0\}^\ast \mid |x| \in N\}$ is a good candidate for being not Turing decidable as well...