If $\frac{b}{a} < \frac{a+b}{b}$, then prove the following:
$\frac{b}{a} < \frac{a + 2b}{a+b}$
$\frac{a+b}{b} < \frac{2a + 3b}{a+2b}$
I have tried to simplify these inequalities, but have gotten no where. Please help!
If $\frac{b}{a} < \frac{a+b}{b}$, then prove the following:
$\frac{b}{a} < \frac{a + 2b}{a+b}$
$\frac{a+b}{b} < \frac{2a + 3b}{a+2b}$
I have tried to simplify these inequalities, but have gotten no where. Please help!
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Hint: Since \begin{align} b^2<a^2+ab \end{align} then it follows \begin{align} b^2+ab<a^2+2ab. \end{align}