Prove using the epsilon definition that the limit of the sequence, $(f:\mathbb{N}\to\mathbb{R}) \{a_n\}=n^{\frac{1}{n}}$ as $n\to\infty$ is equal to 1

Question

Prove using the definition

$\forall \epsilon>0, \exists N\in\mathbb{N}, s.t. \quad \forall n>N,$ we have $\quad \mid a_n-L\mid<\epsilon$