Proving an inequality with absolute values

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Can anyone explain the second bullet point on the following answer?

I am trying to understand how this inequality is proven:

$$\delta(A,B)=|A|+|B|=|A|+|B-C+C|\leq |A|+|C|+|B-C|=\delta(A,C)+\delta(C,B)$$

How does one conclude that the inequality is correct and also how are these absolute values manipulated? If anyone can explain this step by step please.

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First of all a useful zero is filled in and then a simple application of the triangle inequality follows which is $$|x + y| \le |x| +|y|$$

In more simple steps: $$\begin{align} |B| &= |B + 0| \\ &= |B + (C-C)| \\ &= |(B-C) + C| \\ &\le |B-C| + |C|\end{align}$$

So it follows: $$|A| + |B| \le |A| + |B-C| + |C|$$