
In the above image, AP is bisector of the angle BAC and DP is a perpendicular bisector of the segment BC.
How can it be proved that the points E, D, F are colinear?

In the above image, AP is bisector of the angle BAC and DP is a perpendicular bisector of the segment BC.
How can it be proved that the points E, D, F are colinear?
Note that $P$ is the mid-point of the minor arc BC of the circumcircle ABC. So EDF is the Simson line of the point $P$.