I am trying to determine and prove the limit for the function $f(x,y)=\frac{y^2-4|y|-2|x|}{|x|+2|y|}$ after setting $y=mx$ I found out that the limit is not dependent on m and -2 is a potential candidate for the limit so I set up my equation for the squeeze theorem $\lim_{(x,y)\to(0,0)} |\frac{y^2-4|y|-2|x|}{|x|+2|y|}+2|=\lim_{(x,y)\to(0,0)}\frac{y^2}{|x|+2|y|}$ and from this point on I'm having a bit of trouble to set up an inequality to satisfy the squeeze theorem. Would I be able to claim that $y^2 \leq y^2(|x|+2|y|)$
2026-05-06 06:05:55.1778047555
Proving Multivariable limit Exists
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2
HINT:
Note that
$$ |x|+2 |y|\ge 2|y|$$
Can you finish now?