Proving Poincare disk lines are orthogonal to the unit circle.

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I'm doing self study with the book "Continuous Symmetry," and I had one question about proving the incidence axioms for the Poincare disk.

I'm to prove, using analytic geometry, that the circle $C$ meets the unit circle orthogonally iff $$ C := \{(x,y) : (x - a)^2 + (y - b)^2 = a^2 + b^2 - 1\} $$

I was able to prove the necessary portion, yet the authors say I need to use some possibly messy algebra to get the orthogonality from $$ r^2 = a^2 + b^2 -1. $$ I see I could use the converse of the pythagorean theorem to get the right angles, but I feel like I'm missing an easier solution that the authors intended.

Any hints would be appreciated.

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I don't know where the "possibly messy algebra" comes in. This seems pretty straightforward:

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$$\overline{OT}\perp\overline{PT} \quad\iff\quad r^2 + 1^2 = a^2 + b^2$$