I am trying to understand how the Knot Group sits inside of knot theory.
I am giving a talk on a short paper I read in the subject, and I would like to motivate it a little. Not being well read in this matter, my naive assumptions are these:
- Knot Theory (mostly) cares about the classification of knots - being able to tell two of them apart.
- The Knot Group is an invariant, hence different knot groups imply different knots.
But from these basic assumptions I'm not sure how to answer the question "Why do people study homomorphisms going out of knot groups?"
I could give an answer like "because its interesting" but that feels unsatisfying. I would appreciate any insight on this.
Even a person interested solely in classifying knots should be interested in studying homomorphisms going out of knot groups, for the following reasons.
Suppose you have a knot $K$ that you suspect is not equivalent to the trivial knot. How would you prove it?
Since the fundamental group of the complement of a trivial knot is an infinite cyclic group, one method would be to prove that the group $\pi_1(S^3-K)$ is not infinite cyclic. How would you do that?
As an example, let $K \subset S^3$ be the figure eight knot. One reason $K$ is not a trivial knot is because there is a surjective homomorphism from the group $\pi_1(S^3-K)$ onto the dihedral group of order $10$. This is an exercises about the knot group that might be found in knot theory books, and I will leave it to you to look this up, or to figure it out using some presentation of $\pi_1(S^3-K)$ such as the Wirtinger presentation. This suffices to prove that the group $\pi_1(S^3-K)$ is not infinite cyclic, because the only groups onto which an infinite cyclic group can surject are other cyclic groups; but the dihedral group of order $10$ is not cyclic, it is not even abelian.