Q($\sqrt[3]{2}$) - Unique Factorisation Domain?

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I am considering the set of "integers" of the from

$$ a+b\sqrt[3]{2} + c\sqrt[3]{4} $$

where $a,b,c$ are integers. It is easy to show this field is closed under addition and multiplication. I then wish to determine whether Unique Factorisation holds for these integers. Motivated by other examples such as the Gaussian Integers and the Eisenstein Integers, I attempt to define a norm for these integers such that $ N(ab) = N(a)*N(b) $ and the norm always an integer, to then show the field is Euclidean and hence a Unique Factorisation Domain. However, here I get stuck. Unlike the Gaussian and Eisenstein integers, I cannot see how to define the Norm for this field.

Thanks in advance.

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make this CW;

the result mentioned by Robert Soupe is page 327, Example 12.6.9, Introductory Algebraic Number Theory by Alaca and Williams, http://www.amazon.com/Introductory-Algebraic-Number-Theory-Saban/dp/0521540119

See primes represented integrally by a homogeneous cubic form

The part that was done entirely was class number one, (rational) primes $q \equiv 2 \pmod 3,$ also $p = u^2 + 27 v^2.$

My belief, with calculation done for a different norm form, is that when $q = 4 u^2 +2uv+7v^2,$ with integers $u,v$ (not necessarily positive), whenever we have $$ a^3 + 2 b^3 + 4 c^3 - 6abc \equiv 0 \pmod q, $$ THEN $$ a,b,c \equiv 0 \pmod q. $$ The first few such primes are $$ 7, 13, 19, 37, 61, 67, 73, 79, 97, 103, 139, 151, 163, 181, 193, 199, $$ NOTE: This has been confirmed by Noam Elkies. Also note that these are precisely the primes for which there is no cube root of $2.$

I actually have the IANT book somewhere, I will check. Meanwhile, a complete proof for everything for a different norm form is at https://mathoverflow.net/questions/127160/numbers-integrally-represented-by-a-ternary-cubic-form