Quadratic Diophantine Equation $x^2 + 2y^2 = 2013$

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Find integer values of $x$ and $y$ (if any) such that $x^2 + 2y^2 = 2013$.

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The equation is not solvable modulo $8$, hence there are no integer solutions.

You can see this by considering $x^2\equiv 0,1$ or $4$ modulo $8$ for every $x$.