Quadratic Equation by Factoring

Question

My son has this problem on his homework and I can't figure out the process to solve this equation. The instructions say "Solve each equation by factoring". Can someone help and please show steps?

(7b+1)(7b-5) = 0

Answer 1

When an equation is written as a product of several factors equal to zero, it means that any of these factors can be equal to zero and the equation is satisfied. In this case, we have

$7b+1 = 0$, which leads to $b = -1/7$

or

$7b-5=0$, which yields $b = 5/7$.

Hope this helps.