Quadratic equation $(\ell-m)x^2-5(\ell+m)x-2(\ell -m) =0 $

42 Views Asked by At

If $\ell$, m, n are real,$\ell\ne m$, then the roots by the equation :$(\ell-m)x^2-5(\ell+m)x-2(\ell -m)=0$ are

(A)Real and equal

(B) Complex

(C)Real and Unequal

(D) None of these

My approach is as follow The discriminant $T = 25{\left( {\ell + m} \right)^2} + 8{\left( {\ell - m} \right)^2}$

$T = 33{\ell ^2} + 33{m^2} + 34\ell m$

$T = 33{\left( {\ell + m} \right)^2} - 32\ell m$

not able to approach from here

1

There are 1 best solutions below

0
On BEST ANSWER

Your first $T$ i.e. $25{\left( {\ell + m} \right)^2} + 8{\left( {\ell - m} \right)^2}$ is always positive. So, the roots are real and unequal.