Quadratic equation - LHS RHS cancelling

Question

I am unable to solve this equation: $$\displaystyle\frac{(12x^2+5x-3)}{(4x+3)} = \frac{(6x^2+13x-5)}{(2x+5)}$$ On solving the LHS and RHS become equal and cancel each other. Much grateful if anyone can help me out. Shas

Answer 1

The equation is not defined for $x=-\frac{3}{4}$ and $x=-\frac{5}{2}$. The equation is fulfilled for all other real $x$.