$\frac{2d^2-d-10}{d^2+7d+10} = \frac{d^2-4d+3}{d^2+2d-15}$
What is the optimal solution for finding the value of d?
Factor the quadratics. You can pull out $x+5$ on the left and $x-3$ on the right.
Your expression can be written as
$$ \frac{(2d-5)(d+2)}{(d+5)(d+2)} = \frac{(d-1)(d-3)}{(d+5)(d-3)}.$$
Can you see how to proceed from here?
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Factor the quadratics. You can pull out $x+5$ on the left and $x-3$ on the right.