I have this function: $$f(x)=\frac{x(x^2-3)}{x^3-3x-3}$$ I need to draw its graph. I've tried with a classic study of a function but it cames out a mess. Any idea to simplify the study for draw the graph? Thank you.
2026-04-13 17:26:20.1776101180
On
Qualitative graph for a function of $x^{3}$.
49 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
There are 2 best solutions below
4
On
In order to get a graph of $$f(x)=\frac{x(x^2-3)}{x^3-3x-3}$$
We look at intercepts, asymptotes and a few more points.
$f(x)=0$ gives you your $x$-intercepts.
$$f(x)=0 \implies x(x^2-3)=0 \implies x=0,\pm \sqrt 3$$ $$ x^3-3x-3=0 $$ gives you vertical asymptotes $$ x^3-3x-3=0\implies x=2.1038$$
which is the only vertical asymptote.
$$ \lim _{x\to \pm \infty }f(x) = 1$$
That is $y=1$ is a horizontal asymptote.
We use the above information to sketch a graph.
Then we verify our graph with a graphing utility.
HINT
Note that
$$f(x)=\frac{x(x^2-3)}{x^3-3x-3}=f(x)=\frac{x^3-3x}{x^3-3x-3}=f(x)=1+\frac{3}{x^3-3x-3}$$
For a first sketch
Then for a complete study we need use derivatives.