Given is an analytic function from $M$ to $N$, both equipped with conformal Riemannian metric, say $g$ and $h$ resp.
What might the $h$ norm of the derivative of the function at a point mean?
$\|f'(x)\| $ with respect to the $h$ metric.
Thanks
ADD:
It was used in this context:
d(x,y) < d(f(x),f(y)), both defined by the same metric, x,y,f(x),f(y) are in the same space. And the conclusion is that f is expanding, or $\|f'(x)\| $ > 1 with respect to this metric
The context given makes it clear they are talking about the operator norm. In this context, this can be defined as $$ \|f'(x)\|=\sup\sqrt{\frac{h(f'(x)u,f'(x)u)}{g(u,u)}}, $$ the supremum taken over all nonzero tangent vectors $u$ at $x$.