Question about expressing logarithms

Question

If logb (a) = m and logy (b) = c, then find loga (y) in terms of variable c and m

This is what I have so far

logb (a) = log a / log b

logy (b) = log b / log y

=(log a / log b)(log b / log y)

= log a / log y

= logy (a)

I don't know what to do from this point

Answer 1

Obviously : $\log_{a}y = \frac{\log_{b}y}{\log_{b}a}$ i= $\frac{1}{cm}$

Answer 2

Hint:

$$\log_ba=\frac{\log b}{\log a}=m$$ $$\log_ya=\frac{\log a}{\log y}=c$$